document.write( "Question 189213: a framed picture has length 35 cm and width 25 cm. the picture itself has area 375 sq cm. how far is it from the edge of the picture to the edge of frame if the distance is uniform around the picture? \n" ); document.write( "
Algebra.Com's Answer #141977 by checkley75(3666)\"\" \"About 
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25*35=875 is the total area.
\n" ); document.write( "875-375=500 is the area of the border.
\n" ); document.write( "(25-2x)(35-2x)=500
\n" ); document.write( "875-120x+4x^2=500
\n" ); document.write( "4x^2-120x+875-500
\n" ); document.write( "4x^2-120x+375
\n" ); document.write( "Using the quadratic equation \"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\" we get:
\n" ); document.write( "x=(120+-sqrt[-120^2-4*4*375])/2*4
\n" ); document.write( "x=(120+-sqrt[14,400-6,000])/8
\n" ); document.write( "x=(120+-sqrt[8,400}/8
\n" ); document.write( "x=(120+-91.65)/8
\n" ); document.write( "x=(120-91.65)/8
\n" ); document.write( "x=28.35/8
\n" ); document.write( "x=3.54 ans for the width of the border.
\n" ); document.write( "Proof:
\n" ); document.write( "(25-2*3.54)(35-2*3.54)=500
\n" ); document.write( "(25-7.08)(35-7.08)=500
\n" ); document.write( "(17.92*27.92)=500
\n" ); document.write( "500=500\r
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