document.write( "Question 189213: a framed picture has length 35 cm and width 25 cm. the picture itself has area 375 sq cm. how far is it from the edge of the picture to the edge of frame if the distance is uniform around the picture? \n" ); document.write( "
Algebra.Com's Answer #141976 by jonvaliente(64)![]() ![]() You can put this solution on YOUR website! Let x = distance of the edge of the picture to the edge of the frame \n" ); document.write( " 35-2x = length of the picture \n" ); document.write( " 25-2x = width of the picture\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Subtracting 375 from both sides, and re-arranging the terms, we get:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Factoring, we get:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So, \r \n" ); document.write( "\n" ); document.write( "4x-20=0 and/or x-25=0 \n" ); document.write( "4x=20 x=25 \n" ); document.write( "x=5\r \n" ); document.write( "\n" ); document.write( "We take x=5, because if x=25, then it would make the length of the picture \n" ); document.write( "(35-2x)=35-2*25=35-50=-15 and length cannot be negative.\r \n" ); document.write( "\n" ); document.write( "So the edge of the picture is 5cm away from the edge of the frame. \n" ); document.write( " |