document.write( "Question 189231: I have tried several times to work this problem and cannot seem to get the correct answer. Any help would be great! Thanks!\r
\n" ); document.write( "\n" ); document.write( "A rectangular garden has dimensions of 17 feet by 11 feet. A gravel path of equal width is to be built around the garden. How wide can the path be if there is enough gravel for 288 square feet?
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Algebra.Com's Answer #141971 by jonvaliente(64)\"\" \"About 
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The area of the garden is given by 17 x 11 = 187\r
\n" ); document.write( "\n" ); document.write( "If x=width of the path then the dimensions of the garden with the path would be:\r
\n" ); document.write( "\n" ); document.write( "(17+2x) long by (11+2x) wide (remember that the width of the path would add to all 4 sides)\r
\n" ); document.write( "\n" ); document.write( "The whole garden can have the maximum area of 288+187= square feet, so:\r
\n" ); document.write( "\n" ); document.write( "(2x+17)*(2x+11)=475\r
\n" ); document.write( "\n" ); document.write( "\"4x%5E2%2B56x%2B187=475\"\r
\n" ); document.write( "\n" ); document.write( "Subtracting 475 from both sides, we get:\r
\n" ); document.write( "\n" ); document.write( "\"4x%5E2%2B56x-288=0\"\r
\n" ); document.write( "\n" ); document.write( "Factoring, we get:\r
\n" ); document.write( "\n" ); document.write( "\"%282x%2B36%29%2A%282x-8%29=0\"\r
\n" ); document.write( "\n" ); document.write( "2x+36=0 and/or 2x-8=0\r
\n" ); document.write( "\n" ); document.write( "2x=-36 2x=8
\n" ); document.write( "x=-18 x=4\r
\n" ); document.write( "\n" ); document.write( "We take 4, since the width of the path cannot be negative.\r
\n" ); document.write( "\n" ); document.write( "The width of the path is 4 feet.
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