document.write( "Question 189239This question is from textbook McDougal Littel Algebra 1
\n" ); document.write( ": This is an Area Problem.
\n" ); document.write( "The directions say:Find the dimensions of the rectangle or triangle that has the given area.
\n" ); document.write( "number 44, the area is 34 square meters. the length of the rectangle is (X+11)m and the width is (X-4). I cannot figure out how to start the problem.
\n" ); document.write( "THIS IS URGENT SO CAN YOU PLEASE GET BACK TO ME BEFORE TONIGHT.
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Algebra.Com's Answer #141967 by jonvaliente(64)\"\" \"About 
You can put this solution on YOUR website!
The area of a rectangle is given by the product of its length and width. So from this, we get an equation:\r
\n" ); document.write( "\n" ); document.write( "(x+11)*(x-4)=34\r
\n" ); document.write( "\n" ); document.write( "Using FOIL we get:\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B7x-44=34\"\r
\n" ); document.write( "\n" ); document.write( "Subtracting 34 from both sides, we get:\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B7x-78=0\"\r
\n" ); document.write( "\n" ); document.write( "Factoring this quadratic equation, we get:\r
\n" ); document.write( "\n" ); document.write( "\"%28x%2B13%29%28x-6%29=0\"\r
\n" ); document.write( "\n" ); document.write( "x+13=0 and/or x-6=0\r
\n" ); document.write( "\n" ); document.write( "x=-13 and/or x=6\r
\n" ); document.write( "\n" ); document.write( "If x=-13, then the length of the rectangle, (x+11)=(-13)+11=-2. But length cannot be negative, so we take x=6\r
\n" ); document.write( "\n" ); document.write( "where (x+11)=(6+11)=17=length of the rectangle
\n" ); document.write( "(x-4)=6-4=2=width of the rectangle\r
\n" ); document.write( "\n" ); document.write( "So you now have a rectangle with dimensions 17m x 2m\r
\n" ); document.write( "\n" ); document.write( "Hope this helps.
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