document.write( "Question 189201: I have tried several times to answer these two questions and I can't seem to get it right. Your help would be greatly appreciated!!\r
\n" ); document.write( "\n" ); document.write( "1) A triangle has a base of length 2x + 3 and a height of x + 3 and has an area of 27 square units. Find the length of the base and height. (A= 1/2BH)\r
\n" ); document.write( "\n" ); document.write( "2) A triangle has a base of length 3x + 1 and a height of x + 6 and has an area of 45 square units. Find the length of base and height. (A= 1/2BH) \n" ); document.write( "
Algebra.Com's Answer #141937 by Alan3354(69443)\"\" \"About 
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1) A triangle has a base of length 2x + 3 and a height of x + 3 and has an area of 27 square units. Find the length of the base and height. (A= 1/2BH)
\n" ); document.write( "A = (1/2)*(2x+3)*(x+3) = 27
\n" ); document.write( "(2x+3)*(x+3) = 54
\n" ); document.write( "2x^2 + 9x + 9 = 54
\n" ); document.write( "2x^2 + 9x - 45 = 0
\n" ); document.write( "(2x + 15)*(x - 3) = 0
\n" ); document.write( "x = 3 (ignore the -15)
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\n" ); document.write( "2) A triangle has a base of length 3x + 1 and a height of x + 6 and has an area of 45 square units. Find the length of base and height. (A= 1/2BH)
\n" ); document.write( "2A = (3x+1)*(x+6) = 90
\n" ); document.write( "It's 9 by 10, so x = 3\r
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