document.write( "Question 26344: If y = 9, find the integral values of x and z that satisfy all of the following equations:
\n" ); document.write( "z^x = y^2x
\n" ); document.write( "2^z = (2)(4^x)
\n" ); document.write( "x+y+z = 16\r
\n" ); document.write( "\n" ); document.write( "I'd really appreciate the help! Thanks in advance.
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Algebra.Com's Answer #14193 by longjonsilver(2297)\"\" \"About 
You can put this solution on YOUR website!
ignoring \"z%5Ex+=+y%5E2x\" for now, lets look at the other 2 equations.\r
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\n" ); document.write( "\n" ); document.write( "We can take logs to the base2 with \"2%5Ez+=+%282%29%284%5Ex%29\". First this is rewritten as \"2%5Ez+=+%282%29%282%5E%282x%29%29\". This then becomes \"zlog2+=+log2+%2B+2xlog2\"\r
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\n" ); document.write( "\n" ); document.write( "Now log2 to base2 is 1, so we get\r
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\n" ); document.write( "\n" ); document.write( "\"z+=+1+%2B+2x\"
\n" ); document.write( "--> 2x - z = -1\r
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\n" ); document.write( "\n" ); document.write( "x+y+z = 16
\n" ); document.write( "x+9+z = 16
\n" ); document.write( "--> x + z = 7\r
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\n" ); document.write( "\n" ); document.write( "Add these 2 equations together and we get 3x = 6. Therefore x = 2.\r
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\n" ); document.write( "\n" ); document.write( "Hence, from x+z = 7, we then know that z = 5.\r
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\n" ); document.write( "\n" ); document.write( "So, we have x=2, z=5. Check these values in both of the original equations 2 and 3.\r
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\n" ); document.write( "\n" ); document.write( "Now check in equation 1... \"z%5Ex+=+y%5E2x\". We get \"5%5E2+=+9%5E4\" ie 25 = 6561 which is clearly wrong. So either you copied one of the equations down wrong? or the answer is \"there is no solution to all 3 equations\".\r
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\n" ); document.write( "\n" ); document.write( "jon.
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