document.write( "Question 189170This question is from textbook
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document.write( ": Mr. Wise bought $1950 worth of stock, some at $3.00 per share and some at $4.50 per share. If he bought a total of 450 shares of stock, how many of each did he buy?\r
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document.write( "I have tried to arrange this problem several ways and I still can't come up with the correct answer. I am probably just overthinking it. Can you please show the work you use to obtain the answer so I can see what I'm doing wrong in the set up?\r
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document.write( "Thanks,\r
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document.write( "Kim \n" );
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Algebra.Com's Answer #141928 by jonvaliente(64)![]() ![]() You can put this solution on YOUR website! Let x and y = no of shares bought\r \n" ); document.write( "\n" ); document.write( "3x+4.5y=1950 (1) \n" ); document.write( "x+y=450 (2)\r \n" ); document.write( "\n" ); document.write( "Divide both sides of (1) by 3, we get:\r \n" ); document.write( "\n" ); document.write( "x+1.5y=650 \n" ); document.write( "x+y=450\r \n" ); document.write( "\n" ); document.write( "Subtract (2) from (1), we get:\r \n" ); document.write( "\n" ); document.write( "0.5y=200\r \n" ); document.write( "\n" ); document.write( "y=400\r \n" ); document.write( "\n" ); document.write( "x+400=450 \n" ); document.write( "x=50\r \n" ); document.write( "\n" ); document.write( "So Mr. Wise bought 50 of $3.00 share and 400 of $4.50 share \n" ); document.write( " |