document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=189192>Question 189192</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help with this problem: The sum of six times Jack's age and five times Larry's age is 63. Jack is one year less than three times as old as Larry.  Find their ages. Could you also provide me with the equations?\r<BR>\n" );
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document.write( "Please help! Thanks!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #141924 by </B><A HREF=/tutors/aboutme.mpl?userid=jonvaliente><B>jonvaliente(64)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jonvaliente><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jonvaliente><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=141924\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=Larry's age<BR>\n" );
document.write( "    3x-1=Jack's age (one year less 3 times as old as larry)\r<BR>\n" );
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document.write( "6*(3x-1)+5*x=63\r<BR>\n" );
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document.write( "Solving for x:\r<BR>\n" );
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document.write( "18x-6+5x=63<BR>\n" );
document.write( "23x-6=63<BR>\n" );
document.write( "23x=69<BR>\n" );
document.write( "x=3\r<BR>\n" );
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document.write( "Larry is 3 yrs old, and Jack is 8 yrs old </SPAN>\n" );
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