document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=26320>Question 26320</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the dimensions of a rectangle whose perimeter is 46m ans whose area is 126 m^2. (Hint: Let the width be w. Use the perimeter to find the length in terms of w.) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #14191 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=14191\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter=2l+2w=46<BR>\n" );
document.write( "Divide by 2 to get l+w=23<BR>\n" );
document.write( "Also, Area=lw=126<BR>\n" );
document.write( "Use substitution to solve:<BR>\n" );
document.write( "l=23-w<BR>\n" );
document.write( "Sustitute to get: (23-w)(w)=126<BR>\n" );
document.write( "w^2-23w+126=0<BR>\n" );
document.write( "(w-9)(w-14)=0<BR>\n" );
document.write( "w=9 or w=14<BR>\n" );
document.write( "If w=9, then l=23-9=14<BR>\n" );
document.write( "If w=14, then l=23-14=9<BR>\n" );
document.write( "So, the dimentions are 9 and 14.\r<BR>\n" );
document.write( "\n" );
document.write( "Cheers<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );