document.write( "Question 189087: i need you help.! can you please help me solve this equation??\r
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document.write( "the length of a rectangle is 3 inches more than its width.
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document.write( "If the area of the rectangle is 180 square inches, write an equation for the above situation \n" );
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Algebra.Com's Answer #141906 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! the length of a rectangle is 3 inches more than its width. \n" ); document.write( "If the area of the rectangle is 180 square inches, write an equation for the above situation \n" ); document.write( ": \n" ); document.write( "Let x = the width \n" ); document.write( ": \n" ); document.write( "It says,\"the length of a rectangle is 3 inches more than its width.\" therefore: \n" ); document.write( "(x+3) = the length \n" ); document.write( ": \n" ); document.write( "Area = Length * Width, therefore: \n" ); document.write( "A = x * (x+3) \n" ); document.write( "A = x^2 + 3x; is the equation \n" ); document.write( ": \n" ); document.write( "It says, area = 180, therefore: \n" ); document.write( "x^2 + 3x = 180 \n" ); document.write( ": \n" ); document.write( "Subtract 180 from both sides, you have a quadratic equation: \n" ); document.write( "x^2 + 3x - 180 = 0 \n" ); document.write( ": \n" ); document.write( "This will factor to: \n" ); document.write( "(x + 15)(x - 12) = 0 \n" ); document.write( ": \n" ); document.write( "We want the positive solution here: \n" ); document.write( "x = + 12 is the width \n" ); document.write( "then \n" ); document.write( "12 + 3 = 15 is the length \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check by finding the area: 12 * 15 = 180\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |