document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=189111>Question 189111</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Christiana's birthday is four more than three times Rolando's birthday.  Monique's birthday is one more than three times Rolando's.  If they all add up to 54, what are their birthdays? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #141895 by </B><A HREF=/tutors/aboutme.mpl?userid=jonvaliente><B>jonvaliente(64)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jonvaliente><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jonvaliente><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=141895\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=Rolando's birthday<BR>\n" );
document.write( "    3x+4=Christina's birthday<BR>\n" );
document.write( "    3x+1=Monique's birthday\r<BR>\n" );
document.write( "\n" );
document.write( "x+(3x+4)+(3x+1)=54<BR>\n" );
document.write( "7x+5=54<BR>\n" );
document.write( "7x+5-5=54-5<BR>\n" );
document.write( "7x=49<BR>\n" );
document.write( "x=7\r<BR>\n" );
document.write( "\n" );
document.write( "Rolando's birthday is on the 7th, Christina's is on the 25th and Monique's is on the 22nd </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );