document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=189149>Question 189149</A>: <I><SPAN STYLE=\"word-break: break-all;\"> ROOT:5-x = x-3\r<BR>\n" );
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document.write( "do I first set both sides squared to get rid of the root? this again says check all proposed solutions which I don't understand. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #141890 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=141890\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> sqrt(5-x)=x-3<BR>\n" );
document.write( "5-x=x^2-6x+9 square each side.<BR>\n" );
document.write( "x^2-5x+4=0 subtract the left side from the right.<BR>\n" );
document.write( "(x-4)(x-1)=0 factor<BR>\n" );
document.write( "x=4, x=1 These are the proposed solutions. Now you have to put them into the original equation and check to see if the solution is a true one or if it is extraneous.<BR>\n" );
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document.write( "sqrt(5-4)=4-3<BR>\n" );
document.write( "sqrt(1)=1 true<BR>\n" );
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document.write( "sqrt(5-1)=1-3<BR>\n" );
document.write( "2=-2 extraneous<BR>\n" );
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document.write( "Ed<BR>\n" );
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