document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=26312>Question 26312</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the answer to 2xy to the negative second power times y to the fourth power divided by mx to the negative first power times y and all of that to the negative second power. times... 4xy divided by 2x to the negative first power times y to the negative third power and all of that to the second power. ? thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #14188 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=14188\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+%28%28%28y%5E4%29%282xy%29%5E%28-2%29%29%2F%28mx%29%5E%28-1%29%28y%29%29%5E%28-2%29+%2A+%28%284xy%29%2F%28%282x%29%5E%28-1%29%29%28y%5E%28-3%29%29+%29%5E2 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "this is the answer (given that my understanding of your question is correct)\r<BR>\n" );
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document.write( "you could collect powers together eg <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28xy%29%5E6 ALIGN=MIDDLE  ALT=\"%28xy%29%5E6\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "jon.<BR>\n" );
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