document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=189127>Question 189127</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/9780395977255/algebrahomeworkh>algebra and trigonometry</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> i need to know the steps on how to do this problem:<BR>\n" );
document.write( "for each geometric series, find the sum. if the series has no sum, say so.\r<BR>\n" );
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document.write( "1. 24+12+6+3+... </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #141862 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=141862\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> for each geometric series, find the sum. if the series has no sum, say so<BR>\n" );
document.write( "----<BR>\n" );
document.write( " 24+12+6+3+...<BR>\n" );
document.write( "a(1) = 24<BR>\n" );
document.write( "---<BR>\n" );
document.write( "r = 12/24 = 1/2<BR>\n" );
document.write( "------------------<BR>\n" );
document.write( "S(n) = a[1-r^n]/[1-r]<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Limit as n goes to infinity : S(n) = a/(1-r)<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Your problem:<BR>\n" );
document.write( "Sum = 24/(1-(1/2)) = 24/(1/2) = 48<BR>\n" );
document.write( "========================================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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