document.write( "Question 26326: For integers a and b show that
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document.write( "a|b also equals -a|b and a|-b and -a|-b \n" );
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Algebra.Com's Answer #14179 by venugopalramana(3286) You can put this solution on YOUR website! For integers a and b show that \n" ); document.write( "a|b also equals -a|b and a|-b and -a|-b \n" ); document.write( "A|B \n" ); document.write( "HENCE B=M*A WHERE M IS AN INTEGER. \n" ); document.write( "T.P.T. \n" ); document.write( "A|-B...SAY... \n" ); document.write( "WE HAVE FROM B=M*A \n" ); document.write( "-B=-M*A...WHERE -M IS ALSO AN INTEGER \n" ); document.write( "HENCE A|-B....NOTE THE DEFINITION OF PERFECT DIVISION.IT SAYS THAT M HAS TO BE AN INTEGER ONLY.POSITIVE AND NEGATIVE NUMBERS ARE BOTH INTEGERS.SO IT DOES NOT MAKE ANY DIFFERENCE IF M IS PLUS OR MINUS. \n" ); document.write( " |