document.write( "Question 188202: x=2y+1
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document.write( "3x+y=17 \n" );
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Algebra.Com's Answer #141784 by Juhi(44) You can put this solution on YOUR website! x=2y+1 \n" ); document.write( "3x+y=17 - (i)\r \n" ); document.write( "\n" ); document.write( "putting x=2y+1 in (i), \n" ); document.write( "3(2y+1) + y = 17 \n" ); document.write( "6y + 3 + y = 17 \n" ); document.write( "7y = 17 - 3 \n" ); document.write( "7y = 14 \n" ); document.write( "y = 14/7 \n" ); document.write( "y = 2\r \n" ); document.write( "\n" ); document.write( "putting value of y in (i), \n" ); document.write( "3x + 2 = 17 \n" ); document.write( "3x = 15 \n" ); document.write( "x = 5\r \n" ); document.write( "\n" ); document.write( "hence, x=5 and y=2 \n" ); document.write( " |