document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=188932>Question 188932</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A canoeist paddled for 4 hours with a 6-km/h current to reach a campsite.  The return against the same current took 10 hours.  Find the speed of the canoe in still water. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #141757 by </B><A HREF=/tutors/aboutme.mpl?userid=jonvaliente><B>jonvaliente(64)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jonvaliente><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jonvaliente><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=141757\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=speed of the canoe in still water<BR>\n" );
document.write( "    x+6 = speed of the canoe going to the campsite<BR>\n" );
document.write( "    x-6 = speed of the canoe returning from the campsite\r<BR>\n" );
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document.write( "Since distance=speed * time,\r<BR>\n" );
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document.write( "(x+6)*4=(x-6)*10\r<BR>\n" );
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document.write( "4x+24 = 10x-60\r<BR>\n" );
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document.write( "24+60=10x-4x\r<BR>\n" );
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document.write( "84=6x\r<BR>\n" );
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document.write( "x=14\r<BR>\n" );
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document.write( "The canoe travesl at 14kph in still water </SPAN>\n" );
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