document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=188953>Question 188953</A>: <I><SPAN STYLE=\"word-break: break-all;\"> On Saturday morning John walked for 2 hours and then ran for 30 minutes.  Is he ran twice as fast as he walked and he covered 12 miles altogether, how fast did he walk\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #141752 by </B><A HREF=/tutors/aboutme.mpl?userid=jonvaliente><B>jonvaliente(64)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jonvaliente><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jonvaliente><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=141752\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let w = John's speed walking<BR>\n" );
document.write( "    r = John's speed running<BR>\n" );
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document.write( "Since distance = speed * time, then:\r<BR>\n" );
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document.write( "2w + (0.5)r = 12\r<BR>\n" );
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document.write( "r = 2w\r<BR>\n" );
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document.write( "Substituting 2w for r, we get\r<BR>\n" );
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document.write( "2w + (0.5)(2w)=12\r<BR>\n" );
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document.write( "3w = 12\r<BR>\n" );
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document.write( "w=4\r<BR>\n" );
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document.write( "r = 2(4)\r<BR>\n" );
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document.write( "r = 8\r<BR>\n" );
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document.write( "Therefore, John walks at 4mph and runs at 8mph </SPAN>\n" );
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