document.write( "Question 188951: 4+2(3-2y)<_6y-20 \n" ); document.write( "
Algebra.Com's Answer #141750 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"4%2B2%283-2y%29%3C=6y-20\" Start with the given inequality.\r
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\n" ); document.write( "\n" ); document.write( "\"4%2B6-4y%3C=6y-20\" Distribute.\r
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\n" ); document.write( "\n" ); document.write( "\"-4y%2B10%3C=6y-20\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"-4y%3C=6y-20-10\" Subtract \"10\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"-4y-6y%3C=-20-10\" Subtract \"6y\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"-10y%3C=-20-10\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"-10y%3C=-30\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"y%3E=%28-30%29%2F%28-10%29\" Divide both sides by \"-10\" to isolate \"y\". note: Remember, the inequality sign flips when we divide both sides by a negative number. \r
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\n" ); document.write( "\n" ); document.write( "\"y%3E=3\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the answer is \"y%3E=3\"
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