document.write( "Question 188954: This is the question I am having trouble with:\r
\n" ); document.write( "\n" ); document.write( "In his boat, Carl takes 1 and 1/2 times longer to go 72 miles upstream as it takes for him to make the return trip downstream. If the boat cruises at 30mph in still water, what is the speed of the current? \r
\n" ); document.write( "\n" ); document.write( "Thanks for any help.
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Algebra.Com's Answer #141748 by jonvaliente(64)\"\" \"About 
You can put this solution on YOUR website!
Let x=speed of the current
\n" ); document.write( " 30-x = speed of the boat upstream
\n" ); document.write( " 30+x = speed of the boat downstream
\n" ); document.write( " t = time it takes to go downstream\r
\n" ); document.write( "\n" ); document.write( "If it takes 1 and 1/2 times longer to go upstream over the same distance, and distance=speed * time\r
\n" ); document.write( "\n" ); document.write( "\"%2830-x%29%2A1.5t=%2830%2Bx%29%2At\"\r
\n" ); document.write( "\n" ); document.write( "\"45t-1.5xt=30t%2Bxt\"\r
\n" ); document.write( "\n" ); document.write( "\"15t=2.5xt\"\r
\n" ); document.write( "\n" ); document.write( "Dividing both sides by 2.5t to solve for x, we get:\r
\n" ); document.write( "\n" ); document.write( "\"6=x\"\r
\n" ); document.write( "\n" ); document.write( "The speed of the current is 6mph
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