document.write( "Question 188992: Katy leaves City A for City B at 7 A.M., driving at 47 mi/h. At 9 A.M., Jensen leaves City B for City A, driving at 55 mi/h along the same route. If the cities are 298 mi apart, at what time (A.M.) will they meet? [NOTE: Give the number of your answer only - do not label the answer.] \n" ); document.write( "
Algebra.Com's Answer #141741 by jonvaliente(64)\"\" \"About 
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At 9AM (2 hours after Kay left City A), Katy would have already traveled:\r
\n" ); document.write( "\n" ); document.write( "47*2=94 miles\r
\n" ); document.write( "\n" ); document.write( "That leaves a distance of:\r
\n" ); document.write( "\n" ); document.write( "298-94=204 miles left to City B\r
\n" ); document.write( "\n" ); document.write( "If we let x = no of hours that Katy and Jensen needs to travel to cover all 204 miles, then:\r
\n" ); document.write( "\n" ); document.write( "\"47%2Ax+%2B+55%2Ax+=+204\"\r
\n" ); document.write( "\n" ); document.write( "This gives us:\r
\n" ); document.write( "\n" ); document.write( "\"102%2Ax+=+204\"\r
\n" ); document.write( "\n" ); document.write( "Dividing both sides by 102:\r
\n" ); document.write( "\n" ); document.write( "\"x=2\"\r
\n" ); document.write( "\n" ); document.write( "The answer is 2
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