document.write( "Question 188816: A boat took 1 hour and 50 minutes to go 55 km downstream and 3 hours, 40 min to return . Find a boat's rate in still water and the rate of the current. \r
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\n" ); document.write( "ok so distance = 55 km ; time =11/6 hr. ; rate =d/t= 55 ( 11/6)=30 \r
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\n" ); document.write( "distance = 55km; time= (11/3)hr.; rate= d/t=55 (11/3)=15
\n" ); document.write( " equations b+ c =30 kph
\n" ); document.write( " b-c=15kph\r
\n" ); document.write( "\n" ); document.write( "2b=45 kph
\n" ); document.write( "b=22.5 kph ( speed of the boat in still water \r
\n" ); document.write( "\n" ); document.write( "22.5+c=30
\n" ); document.write( "c=30 -22.5=7.5 kph (spped of the current)\r
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\n" ); document.write( "\n" ); document.write( "question: how did one hour and 60 minutes turn into 11/6 hr?
\n" ); document.write( " how did 3 hours and 40 minutes tunr into 11/3hr?
\n" ); document.write( " how did d/t= 55/(11/6) turn into 30 kph?
\n" ); document.write( " how did d/t=55/(11/3) turn into 15 kph?
\n" ); document.write( "please help ! \n" ); document.write( "
Algebra.Com's Answer #141725 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
A boat took 1 hour and 50 minutes to go 55 km downstream and 3 hours, 40 min to return . Find a boat's rate in still water and the rate of the current.
\n" ); document.write( "down stream data
\n" ); document.write( "ok so distance = 55 km ; time = 11/6 hr. ; rate = d/t = 55 ( 11/6)=30\r
\n" ); document.write( "\n" ); document.write( "upstream data
\n" ); document.write( "distance = 55km; time= (11/3)hr.; rate= d/t=55 (11/3)=15
\n" ); document.write( "equations b+ c =30 kph
\n" ); document.write( "b-c=15kph
\n" ); document.write( "2b=45 kph
\n" ); document.write( "b=22.5 kph ( speed of the boat in still water
\n" ); document.write( "22.5+c=30
\n" ); document.write( "c=30 -22.5=7.5 kph (speed of the current)\r
\n" ); document.write( "\n" ); document.write( "question: how did one hour and 60 minutes turn into 11/6 hr?
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\n" ); document.write( "Think you mean,\"how did one hour and 50 minutes turn into 11/6 hr?\"
\n" ); document.write( "We want to work in hrs here since we are using km/hr, to convert 50 min to hrs:
\n" ); document.write( "50/60 = 5/6 hrs, plus the 1 hr which can be written 6/6 hrs, 6/6 + 5/6 = 11/6 hr
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\n" ); document.write( "how did 3 hours and 40 minutes turn into 11/3hr?
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\n" ); document.write( "Convert 40 min to hrs: 40/60 reduces to 4/6 reduces to 2/3 hr
\n" ); document.write( "Add the 3 hr which can be written 9/3 for a total: 9/3 + 2/3 = 11/3 hrs
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\n" ); document.write( "how did d/t= 55/(11/6) turn into 30 kph?
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\n" ); document.write( "Remember rule of dividing fractions, \"Invert the dividing fraction & multiply\"
\n" ); document.write( "55 * 6/11, cancel 11 into 55: 5 * 6 = 30
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\n" ); document.write( "how did d/t=55/(11/3) turn into 15 kph?
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\n" ); document.write( "Like-wise, invert the dividing fraction and multiply 55 * 3/11
\n" ); document.write( "Cancel 11 into 55 and you have 5 * 3 = 15
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\n" ); document.write( "Did this help explain things here? Any questions? \n" ); document.write( "
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