document.write( "Question 188821: According to data from the US Census Bureau, the population P of Cleveland, Ohio (in thousands) in year x can be approximated b P(x)=.08x^2-13.08x+927, where x=0 corresponds to 1950. In what calendar year, is the population about 1,000,000?\r
\n" ); document.write( "\n" ); document.write( "I have tried setting the equation to 1,000,000 (for example: 1,000,000=.08x^2-13.08x+927), but when I solve it, I come out with some outrageous number for the year... could you please show me the steps as to how I am supposed to set it up? I can preform the math, I am just unsure of the set up. \n" ); document.write( "
Algebra.Com's Answer #141724 by ankor@dixie-net.com(22740)\"\" \"About 
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According to data from the US Census Bureau, the population P of Cleveland, Ohio (in thousands) in year x can be approximated b P(x)=.08x^2-13.08x+927, where x=0 corresponds to 1950. In what calendar year, is the population about 1,000,000?
\n" ); document.write( "I have tried setting the equation to 1,000,000 (for example: 1,000,000=.08x^2-13.08x+927),
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\n" ); document.write( "One fact you overlooked, the population is given \"In Thousands\" therefore:
\n" ); document.write( "1,000,000 would be written as 1000
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\n" ); document.write( "The equation would be:
\n" ); document.write( ".08x^2 - 13.08x + 927 = 1000
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\n" ); document.write( ".08x^2 - 13.08x + 927 - 1000 = 0
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\n" ); document.write( ".08x^2 - 13.08x - 73 = 0
\n" ); document.write( "Solve this and you will get a positive solution of approx 169 yrs from 1950 which is 2119
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