document.write( "Question 26340: The triangle A (lower left hand corner of the triangle) B (lower right hand corner) C (top of triangle) =ABC, is an equilateral triangle where each side of the triangle is 6. What is the height of h if h is the dotted vertical line down the center? \r
\n" ); document.write( "\n" ); document.write( "I am having a hard time trying to copy and paste the triangle with my question. Hopefully, you can imagine what I am trying to say. The picture looks like an equilateral triangle w/ a dotted vertical line down the middle. The three sides of the triangle is 6 and the three points of the triangle is ABC. \r
\n" ); document.write( "\n" ); document.write( "Thanks,
\n" ); document.write( "Kristin \n" ); document.write( "

Algebra.Com's Answer #14171 by venugopalramana(3286) $\"\"$ $\"About$

You can put this solution on YOUR website!
LET ABC BE THE TRIANGLE. AND LET AD BE THE HEIGHT SHOWN BY A PERPENDICULAR FRO A TO BC.D IS ON BC. IN TRIANGLES ABD AND ACD WE HAVE
\n" ); document.write( "AB=AC=6
\n" ); document.write( "AD=AD
\n" ); document.write( "ANGLE ADB = 90 = ANGLE ADC
\n" ); document.write( "HENCE THE 2 TRIANGLES ARE IDENTICAL HENCE BD = DC
\n" ); document.write( "BUT BC=BD+DC=6 ...SO BD=DC=3
\n" ); document.write( "IN RIGHT ANGLED TRIANGLE ABD WE HAVE ,ANGLE ADB =90 DEGREES
\n" ); document.write( "HYPOTENUSE = AB =6
\n" ); document.write( "BD =3
\n" ); document.write( "SO
\n" ); document.write( "AD^2+BD^2=AB^2
\n" ); document.write( "AD^2+3^2=6^2
\n" ); document.write( "AD^2=36-9=27
\n" ); document.write( "AD=SQ.RT.27 = 3*SQRT3 \n" ); document.write( "

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