document.write( "Question 188941: On Monday, a local hamburger shop sold a combined total of 448 hamburgers and cheeseburgers. The number of cheeseburgers sold was three times the number of hamburgers sold. How many hamburgers were sold on Monday? \n" ); document.write( "
Algebra.Com's Answer #141701 by jojo14344(1513)\"\" \"About 
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\n" ); document.write( "First Condition of Sales for Monday:
\n" ); document.write( "CB=3HB , more cheeseburgers were sold, 3 times that of hamburgers sold.\r
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\n" ); document.write( "\n" ); document.write( "Second condition:
\n" ); document.write( "CB + HB = 448 \r
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\n" ); document.write( "\n" ); document.write( "Substitute 1st condition into 2nd condition:
\n" ); document.write( "\"highlight%283HB%29%2BHB=448\"
\n" ); document.write( "\"4HB=448\" ----> \"cross%284%29HB%2Fcross%284%29=cross%28448%29112%2Fcross%284%29\"
\n" ); document.write( "\"highlight%28HB=112pcs%29\", number of hamburger sold\r
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\n" ); document.write( "\n" ); document.write( "Go back 1st condition:
\n" ); document.write( "\"CB=3%2A112=highlight%28336pcs%29\", number of cheeseburger sold\r
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\n" ); document.write( "\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo
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