document.write( "Question 188830: A parking lot has a rectangular area of 40,000 sq. yards. The lenght is 200 yards more than twice the width. what are the dimensions of the parking lot? \n" ); document.write( "
Algebra.Com's Answer #141680 by BillKearns2(1)\"\" \"About 
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First I would draw a rectangle.\r
\n" ); document.write( "\n" ); document.write( "The length is 200 yards more than twice the length
\n" ); document.write( "So set length to 2x+200 and the width is x
\n" ); document.write( "The area is 40,000 so: (2x+200)(x)=40000 Since L(w)=Area
\n" ); document.write( "(2x+200)(x)=40000
\n" ); document.write( "2x^2+200x=40000
\n" ); document.write( "Subtract 40,000 from both sides and set to zero
\n" ); document.write( "2x^2+200x-40,000=0
\n" ); document.write( "Factor (may be easier to factor out a 2 first.
\n" ); document.write( "2(x^2+100x-200)=0
\n" ); document.write( "2(x-100)(x+200)=0
\n" ); document.write( "now solve
\n" ); document.write( "2=0 No
\n" ); document.write( "x-100=0: x=100 possibly
\n" ); document.write( "x+200=0: x-200 no, cant have a negative side so use x=100\r
\n" ); document.write( "\n" ); document.write( "so insert 100 into x of original length
\n" ); document.write( "2x+200
\n" ); document.write( "2(100)+200=400\r
\n" ); document.write( "\n" ); document.write( "So, length is 400 and width is 100
\n" ); document.write( "Check your answer by seeing if 400 is actually 2times plus 200 of 100 (It is)
\n" ); document.write( "Check the area Area=LW
\n" ); document.write( "A=400(100)
\n" ); document.write( "A=40,000\r
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