document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=188903>Question 188903</A>: <I><SPAN STYLE=\"word-break: break-all;\">  An art store sells brushes for $1.80 each and tubes of paint for $2.20 each. Sandra spent $1.20 more on brushes than on paint. She spent a total of $27.60. how many brushes and tubes of paint did she buy?\r<BR>\n" );
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document.write( "answer:sandra bought 8 brushes and 6 tubes of paint \r<BR>\n" );
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document.write( "need a full break down of how my book came up with these answers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #141677 by </B><A HREF=/tutors/aboutme.mpl?userid=Mathtut><B>Mathtut(3670)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Mathtut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=141677\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let b and p be the number of brushes and tubes of paint respectively<BR>\n" );
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document.write( "1.80b=2.2p+1.2........eq 1<BR>\n" );
document.write( "1.80b+2.2p=27.60.....eq 2<BR>\n" );
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document.write( "rewrite eq 1 to b=((2.2p+1.2)/1.8) and plug b's value into eq 2<BR>\n" );
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document.write( "1.8((2.2P+1.2)/1.8)+2.2p=27.60<BR>\n" );
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document.write( "2.2P+1.2+2.2p=27.60<BR>\n" );
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document.write( "4.4p=26.4<BR>\n" );
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document.write( "p=6 tubes of paint<BR>\n" );
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document.write( "b=2.2(6)+1.2/1.8=8 brushes </SPAN>\n" );
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