document.write( "Question 188689: If the length of rectangle is 4 dm more than its breadth. If the area of the rectangle is 192 sq.dm, find the length and breadth of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #141660 by jojo14344(1513)\"\" \"About 
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\n" ); document.write( "Let known, breadth=width=W\r
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\n" ); document.write( "\n" ); document.write( "Also, Length = 4dm + W
\n" ); document.write( "Area = 192 sq dm\r
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\n" ); document.write( "\n" ); document.write( "Then, A = L x W = (4 + W)(W) = 192 sq dm
\n" ); document.write( "W^2 + 4W -192 = 0
\n" ); document.write( "(W+16)(W-12)=0
\n" ); document.write( "W=-16dm, discard
\n" ); document.write( "W=12 dm = Breadth\r
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\n" ); document.write( "\n" ); document.write( "Then, L = 4 + 12 = 16 dm = Length\r
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\n" ); document.write( "\n" ); document.write( "Check,
\n" ); document.write( "A = L * W
\n" ); document.write( "192sq dm= (16)(12)
\n" ); document.write( "192sq dm = 192sq dm\r
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\n" ); document.write( "\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo\r
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