document.write( "Question 188831: John has $10,220 to invest. He invests part of his money in a CD at 5% interest and the rest in a savings account at 3.5%. If he earns $442.60 after on year, how much was invested in each account? \n" ); document.write( "
Algebra.Com's Answer #141652 by checkley77(12844)\"\" \"About 
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.05x+.035(10,220-x)=442.60
\n" ); document.write( ".05x+357.70-.035=442.60
\n" ); document.write( ".015x=442.60-357.70
\n" ); document.write( ".015x=84.90
\n" ); document.write( "x=84.90/.015
\n" ); document.write( "x=$5,660 amount invested @ 5%.
\n" ); document.write( "10,220-5,660=4,560 amount invested @ 3.5%
\n" ); document.write( "Proof:
\n" ); document.write( ".05*5,660+.035*4,560=442.60
\n" ); document.write( "283+159.60=442.60
\n" ); document.write( "442.60=442.60
\n" ); document.write( "
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