document.write( "Question 188867: Suppose that the width of a rectangle is 2 inches shorter than the length and that the perimeter of the rectangle is 80.\r
\n" ); document.write( "\n" ); document.write( "Set up an equation for the perimeter involving only L, the length of the rectangle.\r
\n" ); document.write( "\n" ); document.write( "Solve this equation algebraically to find the length of the rectangle. Find the width as well.\r
\n" ); document.write( "\n" ); document.write( "Length ______, Width ______
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Algebra.Com's Answer #141644 by jonvaliente(64)\"\" \"About 
You can put this solution on YOUR website!
Let L = length of the rectangle
\n" ); document.write( " L-2 = width of the rectangle
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\n" ); document.write( "The perimeter of the rectangle is 2*width + 2*length\r
\n" ); document.write( "\n" ); document.write( "\"%28%282%2AL%29%2B%282%2A%28L-2%29%29%29=80\"\r
\n" ); document.write( "\n" ); document.write( "Simplifying...\r
\n" ); document.write( "\n" ); document.write( "\"%282%2AL%29%2B%282%2AL%29-4=80\"\r
\n" ); document.write( "\n" ); document.write( "\"%284%2AL%29-4=80\"\r
\n" ); document.write( "\n" ); document.write( "Add 4 on both sides\r
\n" ); document.write( "\n" ); document.write( "\"%284%2AL%29=84\"\r
\n" ); document.write( "\n" ); document.write( "Divide both sides by 4 and solve for L\r
\n" ); document.write( "\n" ); document.write( "\"L=21\"\r
\n" ); document.write( "\n" ); document.write( "width = L-2
\n" ); document.write( " = 21-2
\n" ); document.write( "width = 19\r
\n" ); document.write( "\n" ); document.write( "Length 21, Width 19\r
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