document.write( "Question 188879: a parking lot has a rectangular area of 40,000 sq yards. the lenght is 200 yards more than twice the width. what are the dimensions of the parking lot? \n" ); document.write( "
Algebra.Com's Answer #141643 by jonvaliente(64)![]() ![]() You can put this solution on YOUR website! Let x = width of the parking lot \n" ); document.write( " 2x + 200 = length of the parking lot (being 200 yards more than twice the width)\r \n" ); document.write( "\n" ); document.write( "The area of the rectangular lot is the length*width\r \n" ); document.write( "\n" ); document.write( "so \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "simplifying...\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "divide both sides by 2 to simplify\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "factoring...\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "possible solutions are x=-500 and x=400. We take x=400 yards as length cannot be negative\r \n" ); document.write( "\n" ); document.write( "so the width of the parking lot is 400 yards and the length is 1000 yards \n" ); document.write( " |