document.write( "Question 188879: a parking lot has a rectangular area of 40,000 sq yards. the lenght is 200 yards more than twice the width. what are the dimensions of the parking lot? \n" ); document.write( "
Algebra.Com's Answer #141643 by jonvaliente(64)\"\" \"About 
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Let x = width of the parking lot
\n" ); document.write( " 2x + 200 = length of the parking lot (being 200 yards more than twice the width)\r
\n" ); document.write( "\n" ); document.write( "The area of the rectangular lot is the length*width\r
\n" ); document.write( "\n" ); document.write( "so \r
\n" ); document.write( "\n" ); document.write( "\"x%2A%282x%2B200%29=40000\"\r
\n" ); document.write( "\n" ); document.write( "simplifying...\r
\n" ); document.write( "\n" ); document.write( "\"2x%5E2%2B200x=40000\"\r
\n" ); document.write( "\n" ); document.write( "divide both sides by 2 to simplify\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B100x=20000\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B100x-20000\"\r
\n" ); document.write( "\n" ); document.write( "factoring...\r
\n" ); document.write( "\n" ); document.write( "\"%28x%2B500%29%2A%28x-400%29=0\"\r
\n" ); document.write( "\n" ); document.write( "possible solutions are x=-500 and x=400. We take x=400 yards as length cannot be negative\r
\n" ); document.write( "\n" ); document.write( "so the width of the parking lot is 400 yards and the length is 1000 yards
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