document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=188875>Question 188875</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how much pure acid should be mix with 2 gallonsof 40% acid solution in order to get a 70%acid solution. can you please show me how to do it my self, thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #141640 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=141640\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how much pure acid should be mix with 2 gallonsof 40% acid solution in order to get a 70%acid solution.<BR>\n" );
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document.write( "2 gals of 40% has 0.8 gals of acid and 1.2 gals of water.<BR>\n" );
document.write( "If acid is added to be 70%, then the 1.2 gals of water will be 30% of the solution.<BR>\n" );
document.write( "If 1.2 gals is 0.3 of the solution, then the total is 4 gallons.  Add 2 gallons to make it 70%.<BR>\n" );
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