document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=188859>Question 188859</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 6x+12=3x+8 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #141624 by </B><A HREF=/tutors/aboutme.mpl?userid=feliz1965><B>feliz1965(151)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=feliz1965><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=141624\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given: 6x + 12 = 3x + 8, solve for x.\r<BR>\n" );
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document.write( "Put the x terms together and the constants together on different sides of the equation.\r<BR>\n" );
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document.write( "Don't forget the change the signs when crossing the equal symbol.  In other words, 3x becomes -3x and 12 becomes -12.\r<BR>\n" );
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document.write( "6x - 3x = 8 - 12\r<BR>\n" );
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document.write( "3x = -4\r<BR>\n" );
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document.write( "x = -4/3\r<BR>\n" );
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