document.write( "Question 188829: Solve the system of equations\r
\n" ); document.write( "\n" ); document.write( "\"+x%5E2+\" + \"+y%5E2+\" = 169
\n" ); document.write( "\"+x%5E2+\" -8y = 104\r
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\n" ); document.write( "\n" ); document.write( "Could you please prvide me with a detailed explanation of how you achieved the solution. Thanks!
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Algebra.Com's Answer #141614 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
x^2 + y^2 = 169
\n" ); document.write( "x^2 - 8y = 104
\n" ); document.write( "-------------------Subtraction eliminates x^2
\n" ); document.write( "y^2 + 8y = 65
\n" ); document.write( "A quadratic equation:
\n" ); document.write( "y^2 + 8y - 65 = 0
\n" ); document.write( "Factors to:
\n" ); document.write( "(y + 13)(y - 5) = 0
\n" ); document.write( "Two solutions
\n" ); document.write( "y = -13
\n" ); document.write( "y = +5
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\n" ); document.write( "Find x when y = -13 using the 1st equation:
\n" ); document.write( "x^2 + (-13)^2 = 169
\n" ); document.write( "x^2 + 169 = 169
\n" ); document.write( "x^2 = 169 - 169
\n" ); document.write( "x^2 = 0
\n" ); document.write( "x = 0
\n" ); document.write( "when y = 5
\n" ); document.write( "x^2 + 5^2 = 169
\n" ); document.write( "x^2 = 169 - 25
\n" ); document.write( "x^2 = 144
\n" ); document.write( "x = \"sqrt%28144%29\"
\n" ); document.write( "x = +/-12
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check solutions x=0, y=-13, in 2nd equation
\n" ); document.write( "0 - 8(-13) = 104
\n" ); document.write( "0 + 104 = 104
\n" ); document.write( ":
\n" ); document.write( "Check solutions x=+/-12, y=5 in 2nd equation
\n" ); document.write( "12^2 - 8(5) = 104
\n" ); document.write( "144 - 40 = 104
\n" ); document.write( ":
\n" ); document.write( "Graphing it,we can see the actual solutions are; x=-12, y=5 and x=+12, y=5:
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