document.write( "Question 188836: ok.well im having a lot of troulble with logs so i have a question.here is my problem...(16 to the 3/4 power - 16 to the 1/4 power)to the -3/2power.
\n" ); document.write( "i have no clue on what to do.please help! \n" ); document.write( "
Algebra.Com's Answer #141612 by Alan3354(69443)\"\" \"About 
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ok.well im having a lot of troulble with logs so i have a question.here is my problem...(16 to the 3/4 power - 16 to the 1/4 power)to the -3/2power.
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\n" ); document.write( "...(16 to the 3/4 power - 16 to the 1/4 power)to the -3/2power.
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\n" ); document.write( "Take it one step at a time
\n" ); document.write( "16 to the 3/4 power
\n" ); document.write( "= (16^(1/4))^3
\n" ); document.write( "16^(1/4) = (2^4)^1/4 = 2
\n" ); document.write( "then, 2^3 = 8
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\n" ); document.write( "The 1st term is 8.
\n" ); document.write( "16^(1/4) is 2 (still).
\n" ); document.write( "The 2nd term is 2
\n" ); document.write( "So now it's:
\n" ); document.write( "(8 - 2)^(-3/2)
\n" ); document.write( "= 6^(-3/2) at least it's shorter
\n" ); document.write( "= 1/(6^(3/2))
\n" ); document.write( "= 1/6 * 1/sqrt(6)
\n" ); document.write( "= 1/6 * sqrt(6)/6
\n" ); document.write( "= \"sqrt%286%29%2F6\"
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