document.write( "Question 26314: Find the dimensions of a rectangle whose perimeter is 46m ans whose area is 126 m^2. (Hint: Let the width be w. Use the perimeter to find the length in terms of w.) \n" ); document.write( "
Algebra.Com's Answer #14159 by Paul(988)![]() ![]() ![]() You can put this solution on YOUR website! Let the length be x \n" ); document.write( "Let the width be y \n" ); document.write( "Now 2(x+y)=46 \n" ); document.write( "2x+2y=46 \n" ); document.write( "x+y=23 \n" ); document.write( "y=23-x (subsitution)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "xy=126 \n" ); document.write( "x(23-x)=126 \n" ); document.write( "23x-x^2=126 \n" ); document.write( " \n" ); document.write( "Factor take out the negative \n" ); document.write( "x=14. \n" ); document.write( "y=23-14 \n" ); document.write( "y=9 \n" ); document.write( "IF you need help on factoring the Quadratic e-mail be baack.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hence, the length is 14 and the width is 9cm. \n" ); document.write( "Paul. \n" ); document.write( " |