document.write( "Question 26314: Find the dimensions of a rectangle whose perimeter is 46m ans whose area is 126 m^2. (Hint: Let the width be w. Use the perimeter to find the length in terms of w.) \n" ); document.write( "
Algebra.Com's Answer #14159 by Paul(988)\"\" \"About 
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Let the length be x
\n" ); document.write( "Let the width be y
\n" ); document.write( "Now 2(x+y)=46
\n" ); document.write( "2x+2y=46
\n" ); document.write( "x+y=23
\n" ); document.write( "y=23-x (subsitution)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "xy=126
\n" ); document.write( "x(23-x)=126
\n" ); document.write( "23x-x^2=126
\n" ); document.write( "\"x%5E2-23x%2B126=0%2Cx\"
\n" ); document.write( "Factor take out the negative
\n" ); document.write( "x=14.
\n" ); document.write( "y=23-14
\n" ); document.write( "y=9
\n" ); document.write( "IF you need help on factoring the Quadratic e-mail be baack.\r
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\n" ); document.write( "\n" ); document.write( "Hence, the length is 14 and the width is 9cm.
\n" ); document.write( "Paul.
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