document.write( "Question 188769This question is from textbook An Applied Approach
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document.write( ": The length of a rectangle is 2 ft more than twice the width. The area of the rectangle is 84ft2. Find the length and width of the rectangle. \n" );
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Algebra.Com's Answer #141581 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The length of a rectangle is 2 ft more than twice the width. The area of the rectangle is 84ft2. Find the length and width of the rectangle. \n" ); document.write( "------------------- \n" ); document.write( "Let the width be \"x\" ft. \n" ); document.write( "Then the length is \"2x+2\" ft. \n" ); document.write( "-------------------------------------- \n" ); document.write( "Area = WL \n" ); document.write( "84 = x(2x+2) \n" ); document.write( "42 = x(x+1) \n" ); document.write( "x^2 + x - 42 = 0 \n" ); document.write( "(x+7)(x-6) = 0 \n" ); document.write( "---- \n" ); document.write( "x = 6 ft (width) \n" ); document.write( "2x+2 = 12+2 = 14 ft (length) \n" ); document.write( "=============================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |