document.write( "Question 188769This question is from textbook An Applied Approach
\n" ); document.write( ": The length of a rectangle is 2 ft more than twice the width. The area of the rectangle is 84ft2. Find the length and width of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #141581 by stanbon(75887)\"\" \"About 
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The length of a rectangle is 2 ft more than twice the width. The area of the rectangle is 84ft2. Find the length and width of the rectangle.
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\n" ); document.write( "Let the width be \"x\" ft.
\n" ); document.write( "Then the length is \"2x+2\" ft.
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\n" ); document.write( "Area = WL
\n" ); document.write( "84 = x(2x+2)
\n" ); document.write( "42 = x(x+1)
\n" ); document.write( "x^2 + x - 42 = 0
\n" ); document.write( "(x+7)(x-6) = 0
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\n" ); document.write( "x = 6 ft (width)
\n" ); document.write( "2x+2 = 12+2 = 14 ft (length)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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