document.write( "Question 188758: How do I complete the square if the sum look like this: 5x^2 - x - 2=0 \n" ); document.write( "
Algebra.Com's Answer #141573 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Solve by completing the square:
\n" ); document.write( "\"5x%5E2-x-2+=+0\" To complete the square, you need to have the \"x%5E2\" coefficient = 1, so divide through by 5.
\n" ); document.write( "\"%285x%5E2-x-2%29%2F5+=+0\" Simplify.
\n" ); document.write( "\"%281%2F5%29x%5E2-%281%2F5%29x-2%2F5+=+0\" Now add \"2%2F5\" to both sides.
\n" ); document.write( "\"%281%2F5%29x%5E2-%281%2F5%29x+=+2%2F5\" Complete the square in x by adding the square of half the x-coefficient \"%281%2F10%29%5E2+=+1%2F100\" to both sides.
\n" ); document.write( "\"%281%2F5%29x%5E2-%281%2F5%29x%2B1%2F100+=+2%2F5+%2B+1%2F100\" Factor the left side and simplify the right side.
\n" ); document.write( "\"%28x-1%2F10%29%5E2+=+41%2F100\" Now take the square root of both sides.
\n" ); document.write( "\"x-1%2F10+=+%28sqrt%2841%29%29%2F10\" or \"x-1%2F10+=+-%28sqrt%2841%29%29%2F10\" Add \"1%2F10\" to both sides of each of these.
\n" ); document.write( "\"x+=+1%2F10%2B-sqrt%2841%29%2F10\"
\n" ); document.write( "\"highlight%28x+=+1%2F10+%2B%28sqrt%2841%29%29%2F10%29\" or \"highlight%28x+=+1%2F10+-+%28sqrt%2841%29%29%2F10%29\"
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