document.write( "Question 188728This question is from textbook
\n" ); document.write( ": If Rachel jobs for awhile at 8 km/h and then walks at 5 km/h, she travels 23 km. If she reverses the amoun of time spent jogging and walking, she travels 6 km farther. Find her total travelling time. \n" ); document.write( "
Algebra.Com's Answer #141547 by stanbon(75887)\"\" \"About 
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If Rachel jogs for a while at 8 km/h and then walks at 5 km/h, she travels 23 km. If she reverses the amount of time spent jogging and walking, she travels 6 km farther. Find her total traveling time.
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\n" ); document.write( "23 km trip:
\n" ); document.write( "8x + 5y = 23
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\n" ); document.write( "29 km trip
\n" ); document.write( "5x + 8y = 29
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\n" ); document.write( "Modify the two equations to set them up for elimination:
\n" ); document.write( "40x + 25y = 115
\n" ); document.write( "40x + 64y = 232
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\n" ); document.write( "39y = 117
\n" ); document.write( "y = 3 hrs
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\n" ); document.write( "Substitute into 8x + 5y = 23 to solve for \"x\":
\n" ); document.write( "8x + 5*3 = 23
\n" ); document.write( "8x = 8
\n" ); document.write( "x = 1 hr
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\n" ); document.write( "Total time: x + y = 1+3 = 4 hrs
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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