document.write( "Question 188728This question is from textbook
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document.write( ": If Rachel jobs for awhile at 8 km/h and then walks at 5 km/h, she travels 23 km. If she reverses the amoun of time spent jogging and walking, she travels 6 km farther. Find her total travelling time. \n" );
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Algebra.Com's Answer #141547 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! If Rachel jogs for a while at 8 km/h and then walks at 5 km/h, she travels 23 km. If she reverses the amount of time spent jogging and walking, she travels 6 km farther. Find her total traveling time. \n" ); document.write( "-------------------------------------------------- \n" ); document.write( "23 km trip: \n" ); document.write( "8x + 5y = 23 \n" ); document.write( "--------------------------- \n" ); document.write( "29 km trip \n" ); document.write( "5x + 8y = 29 \n" ); document.write( "-------------------- \n" ); document.write( "Modify the two equations to set them up for elimination: \n" ); document.write( "40x + 25y = 115 \n" ); document.write( "40x + 64y = 232 \n" ); document.write( "---------------------- \n" ); document.write( "39y = 117 \n" ); document.write( "y = 3 hrs \n" ); document.write( "------------------- \n" ); document.write( "Substitute into 8x + 5y = 23 to solve for \"x\": \n" ); document.write( "8x + 5*3 = 23 \n" ); document.write( "8x = 8 \n" ); document.write( "x = 1 hr \n" ); document.write( "------------------------- \n" ); document.write( "Total time: x + y = 1+3 = 4 hrs \n" ); document.write( "================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |