document.write( "Question 188716: Length of a Line Segment
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Algebra.Com's Answer #141521 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Remember, the distance between any two points and is\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%28x%5B1%5D-x%5B2%5D%29%5E2%2B%28y%5B1%5D-y%5B2%5D%29%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "In this case, is the point (x,1) and is the point (2,6)\r
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\n" ); document.write( "\n" ); document.write( "Now matching corresponding coordinates, we get \"x%5B1%5D=x\", \"y%5B1%5D=1\", \"x%5B2%5D=2\", and \"y%5B2%5D=6\"\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%28x%5B1%5D-x%5B2%5D%29%5E2%2B%28y%5B1%5D-y%5B2%5D%29%5E2%29\" Start with the distance formula\r
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\n" ); document.write( "\n" ); document.write( "\"5=sqrt%28%28x-2%29%5E2%2B%281-6%29%5E2%29\" Plug in \"d=5\" (the given distance) \"x%5B1%5D=x\", \"y%5B1%5D=1\", \"x%5B2%5D=2\", and \"y%5B2%5D=6\" (the given coordinates)\r
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\n" ); document.write( "\n" ); document.write( "The goal now is to solve for \"x\":\r
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\n" ); document.write( "\n" ); document.write( "\"5=sqrt%28%28x-2%29%5E2%2B%28-5%29%5E2%29\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"5=sqrt%28%28x-2%29%5E2%2B25%29\" Square -5 to get 25\r
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\n" ); document.write( "\n" ); document.write( "\"5%5E2=%28x-2%29%5E2%2B25\" Square both sides (to eliminate the square root)\r
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\n" ); document.write( "\n" ); document.write( "\"25=%28x-2%29%5E2%2B25\" Square 5 to get 25\r
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\n" ); document.write( "\n" ); document.write( "\"25-25=%28x-2%29%5E2\" Subtract 25 from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"0=%28x-2%29%5E2\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-2%29%5E2=0\" Rearrange the equation\r
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\n" ); document.write( "\n" ); document.write( "\"x-2=0%2B-sqrt%280%29\" Take the square root of both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"x-2=sqrt%280%29\" or \"x-2=-sqrt%280%29\" Break up the \"plus/minus\" to form two equations.\r
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\n" ); document.write( "\n" ); document.write( "\"x-2=0\" or \"x-2=0\" Take the square root of \"0\" to get \"0\".\r
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\n" ); document.write( "\n" ); document.write( "\"x=2%2B0\" or \"x=2-0\" Add \"2\" to both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"x=2\" or \"x=2\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"x=2\" Remove the duplicate solution\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the only solution is \"x=2\".\r
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\n" ); document.write( "\n" ); document.write( "So the point (2,1) is 5 units from (2,6)\r
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\n" ); document.write( "\n" ); document.write( "Note: if you plot the points on a coordinate plane and count the number of units one point is from another, you'll find that the two points are 5 units apart.
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