document.write( "Question 188704: Can someone please help me. I've submitted this problem yesterday at 10:00 am and today at 1:00pm and still haven't gotten a response. \r
\n" ); document.write( "\n" ); document.write( "Suppose you work in an office and your current cubicle is a square. The company is moving and your new cubicle will be 2 feet longer on one side and 3 feet shorter on the other. \r
\n" ); document.write( "\n" ); document.write( "a) Determine the dimensions of your new cubicle based on your original square, which is x feet per side.\r
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\n" ); document.write( "\n" ); document.write( " x + 2 would be the side 2 feet longer.\r
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\n" ); document.write( "\n" ); document.write( " x - 3 would be the side 3 feet shorter.\r
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\n" ); document.write( "\n" ); document.write( "b) Write the equation for the area of your new cubicle.\r
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\n" ); document.write( "\n" ); document.write( " (x + 2)(x - 3) Area = Length * Width\r
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\n" ); document.write( "\n" ); document.write( "Using the FOIL method to multiply the polynomials\r
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\n" ); document.write( "\n" ); document.write( "Note the \"FOILy face\".\r
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\n" ); document.write( "\n" ); document.write( "c) If your old cubicle was 8 feet by 8 feet, is your new cubicle larger or smaller and by how much?\r
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\n" ); document.write( "\n" ); document.write( "8 * 8 = 64 ft2 Size of original cubicle.\r
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\n" ); document.write( "\n" ); document.write( "82 - 8 - 6 Substitute in value of x which is 8 in this case.\r
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\n" ); document.write( "\n" ); document.write( "64 - 14\r
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\n" ); document.write( "\n" ); document.write( "50 ft2 Size of new cubicle\r
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\n" ); document.write( "\n" ); document.write( "64 - 50 = 14 ft2 New cubicle is 14 square feet smaller than old cubicle.\r
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\n" ); document.write( "\n" ); document.write( "Using the example above, develop a similar problem in which you change the size of a shape. Show the same steps as above. No graphics needed.
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Algebra.Com's Answer #141515 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
a) You are correct. The dimensions are \"x%2B2\" by \"x-3\"\r
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\n" ); document.write( "\n" ); document.write( "b) \r
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\n" ); document.write( "\n" ); document.write( "Area: \"A=%28x+%2B+2%29%28x+-+3%29=x%5E2-3x%2B2x-6=x%5E2-x-6\"\r
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\n" ); document.write( "\n" ); document.write( "So the area is \"A=x%5E2-x-6\"\r
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\n" ); document.write( "\n" ); document.write( "c)\r
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\n" ); document.write( "\n" ); document.write( "Original Area: \"A=x%5E2=8%5E2=64\"\r
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\n" ); document.write( "\n" ); document.write( "New Area: \"A=x%5E2-x-6=%288%29%5E2-%288%29-6=64-8-6=50\"\r
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\n" ); document.write( "\n" ); document.write( "Difference in Areas: \"64-50=14\"\r
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\n" ); document.write( "\n" ); document.write( "New cubicle is smaller by 14 square feet (since \"A%5Bn%5D%3CA%5Bo%5D\"). You are correct.\r
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\n" ); document.write( "\n" ); document.write( "Let's say that we start with a square again with side lengths of \"x\". Now one side is lengthened by 5 while the other is shortened by 2. \r
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\n" ); document.write( "\n" ); document.write( "So the new dimensions would be \"x%2B5\" by \"x-2\"\r
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\n" ); document.write( "\n" ); document.write( "The new area would be \"A=%28x%2B5%29%28x-2%29=x%5E2-2x%2B5x-15=x%5E2%2B3x-15\"\r
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\n" ); document.write( "\n" ); document.write( "Finally, if \"x=8\", then \r
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\n" ); document.write( "\n" ); document.write( "Old area: \"A=8%5E2=64\"\r
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\n" ); document.write( "\n" ); document.write( "New area: \"A=%288%29%5E2%2B3%288%29-15=64%2B24-15=73\"\r
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\n" ); document.write( "\n" ); document.write( "Difference in areas: \"73-64=9\"\r
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\n" ); document.write( "\n" ); document.write( "New area is now 9 square feet larger than the old area.
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