document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=26308>Question 26308</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3)	Use the geometric series of numbers 1, 1/2, 1/4, 1/8,…to find the following:<BR>\n" );
document.write( "a)	What is r, the ratio between 2 consecutive terms? <BR>\n" );
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document.write( "b)	Using the formula for the nth term of a geometric series, what is 10th term? Answer: <BR>\n" );
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document.write( "c)	Using the formula for the nth term of a geometric series, what is 12th term? Answer:	<BR>\n" );
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document.write( "d)	What observation can make about these sums? In particular, what number does it appear that the sum will always be smaller than?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #14151 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=14151\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a) r=(1/2)/1=1/2<BR>\n" );
document.write( "b) 10th term = (1st term)(1/2)^(10-1)<BR>\n" );
document.write( "      = (1/2)^9 = 1/512<BR>\n" );
document.write( "c) 12th term = (1st term)(1/2)^11<BR>\n" );
document.write( "      = 1/2048<BR>\n" );
document.write( "d) Each term is (1/2) the term before it.  The sum of<BR>\n" );
document.write( "the terms up to any point will be less than 2.<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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