document.write( "Question 188693: Prove that if \"3x%5E2%2B6=18\" and x<0, then x=-2 is true. \n" ); document.write( "
Algebra.Com's Answer #141506 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\"3x%5E2%2B6=18\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"3x%5E2%2B6-18=0\" Subtract 18 from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"3x%5E2-12=0\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "Notice we have a quadratic equation in the form of \"ax%5E2%2Bbx%2Bc\" where \"a=3\", \"b=0\", and \"c=-12\"\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for x\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29\" Start with the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-%280%29+%2B-+sqrt%28+%280%29%5E2-4%283%29%28-12%29+%29%29%2F%282%283%29%29\" Plug in \"a=3\", \"b=0\", and \"c=-12\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%280+%2B-+sqrt%28+0-4%283%29%28-12%29+%29%29%2F%282%283%29%29\" Square \"0\" to get \"0\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%280+%2B-+sqrt%28+0--144+%29%29%2F%282%283%29%29\" Multiply \"4%283%29%28-12%29\" to get \"-144\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%280+%2B-+sqrt%28+0%2B144+%29%29%2F%282%283%29%29\" Rewrite \"sqrt%280--144%29\" as \"sqrt%280%2B144%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%280+%2B-+sqrt%28+144+%29%29%2F%282%283%29%29\" Add \"0\" to \"144\" to get \"144\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%280+%2B-+sqrt%28+144+%29%29%2F%286%29\" Multiply \"2\" and \"3\" to get \"6\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%280+%2B-+12%29%2F%286%29\" Take the square root of \"144\" to get \"12\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%280+%2B+12%29%2F%286%29\" or \"x+=+%28-0+-+12%29%2F%286%29\" Break up the expression. \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%2812%29%2F%286%29\" or \"x+=++%28-12%29%2F%286%29\" Combine like terms. \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+2\" or \"x+=+-2\" Simplify. \r
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\n" ); document.write( "\n" ); document.write( "So the answers are \"x+=+2\" or \"x+=+-2\"\r
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\n" ); document.write( "\n" ); document.write( "However, since \"x%3C0\", this means that \"x\" is negative. So this means that \"x=-2\" is the only solution (if the inequality restriction is applied).
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