document.write( "Question 188604: Solve each equation. Round to the nearest hundredth.
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document.write( "() means base number \r
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document.write( "log 5x = 3 \r
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document.write( "log x = 42. 102x = 40\r
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document.write( "10^2x=40\r
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document.write( "log (7x + 3) = 2 \r
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document.write( "2log x - log 5 = 4 \r
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document.write( "log(5)(3x + 10) - 3 log(5)4 = 2 \n" );
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Algebra.Com's Answer #141464 by feliz1965(151)![]() ![]() ![]() You can put this solution on YOUR website! Here is a tip:\r \n" ); document.write( "\n" ); document.write( "No one is going to solve all these questions if you place them all together in a single post.\r \n" ); document.write( "\n" ); document.write( "Post each question separately.\r \n" ); document.write( "\n" ); document.write( "I will do log (7x + 3) = 2 only.\r \n" ); document.write( "\n" ); document.write( "Here, the base = 10 and exponent = 2.\r \n" ); document.write( "\n" ); document.write( "We isolate 7x + 3 on one side of the equation.\r \n" ); document.write( "\n" ); document.write( "10^2 = 7x + 3\r \n" ); document.write( "\n" ); document.write( "100 = 7x + 3\r \n" ); document.write( "\n" ); document.write( "100 - 3 = 7x\r \n" ); document.write( "\n" ); document.write( "97 = 7x\r \n" ); document.write( "\n" ); document.write( "97/7 = x\r \n" ); document.write( "\n" ); document.write( "I will let you finish. To do so, divide 97 by 7 and then round off to the nearest hundredths. Can you take it from here?\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |