document.write( "Question 188603: Mike can assemble a computer table in 40 minutes and I can do it in 60 minutes. If Mike works for 20 minutes before I join him, how long will it take us to finish? \n" ); document.write( "

Algebra.Com's Answer #141431 by ptaylor(2198) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let x=amount of time it will take you and Mike to finish
\n" ); document.write( "Mike works at the rate of 1/40 computer per min\r
\n" ); document.write( "\n" ); document.write( "You work at the rate of 1/60 computer per min\r
\n" ); document.write( "\n" ); document.write( "Together you and Mike work at the rate of 1/40 +1/60=3/120 + 2/120=5/120=1/24 computer per min\r
\n" ); document.write( "\n" ); document.write( "Before you start, Mike as already assembled (1/40)*20=1/2 of the computer, leaving 1/2 of the computer yet to be done. So the question is how long will it take you and Mike working together to do the remaining half of the computer\r
\n" ); document.write( "\n" ); document.write( "Now our equation to solve is:
\n" ); document.write( "(1/24)*x=1/2 (1/2 of the computer, that is) Multiply each side by 24
\n" ); document.write( "x=12 min------------------amount of time it will take you and Mike to finish\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "(1/24)*12=1/2
\n" ); document.write( "1/2=1/2\r
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor \n" ); document.write( "

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