document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=188635>Question 188635</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Question: The sum of two digits of a number is 10. If the digits chane their places, the value of the number is decreased by 18. Find the number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #141429 by </B><A HREF=/tutors/aboutme.mpl?userid=Mathtut><B>Mathtut(3670)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Mathtut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=141429\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the number be ab.....which can be written as 10a+b......the number reversed would be ba.....which can be written as 10b+a<BR>\n" );
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document.write( "a+b=10.......eq 1<BR>\n" );
document.write( "10b+a=10a+b-18...eq 2--->9b-9a=-18<BR>\n" );
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document.write( "rewrite eq 1 to a=10-b and plug it into eq 2<BR>\n" );
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document.write( "9b-9(10-b)=-18<BR>\n" );
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document.write( "9b-90+9b=-18<BR>\n" );
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document.write( "18b=72<BR>\n" );
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document.write( "b=4<BR>\n" );
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document.write( "a=10-4 =6<BR>\n" );
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document.write( "so our number is 64\r<BR>\n" );
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