document.write( "Question 188602: Give the vertex, focus, directrix, and the distance across parabola at focus, and then graph the parabola.\r
\n" ); document.write( "\n" ); document.write( "x^2+6x+2y+15=0 \n" ); document.write( "

Algebra.Com's Answer #141402 by Mathtut(3670) $\"\"$ $\"About$

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$\"2y=-x%5E2-6x-15\"$
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\n" ); document.write( " $\"y=-1%2F2%28x%5E2%2B6x%2B9%29-15%2F2%2B9%2F2\"$
\n" ); document.write( ":
\n" ); document.write( " $\"y=-1%2F2%28x%2B3%29%5E2-3\"$
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\n" ); document.write( "vertex is at (-3,-3)
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\n" ); document.write( "1/4p=-1/2
\n" ); document.write( ":
\n" ); document.write( "p=-1/2
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\n" ); document.write( "directrix is at y=-5/2
\n" ); document.write( "focus is at (-3,-7/2)
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\n" ); document.write( "distance across parabola is abs value of 4p which equals abs value of 4(-1/2)= 2:
\n" ); document.write( " $\"graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C%28-1%2F2%29%28x%2B3%29%5E2-3%29\"$ \n" ); document.write( "

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