document.write( "Question 26288: How would you find x and y by elimination of substituting this problem?\r
\n" ); document.write( "\n" ); document.write( " -3x+2y=-6
\n" ); document.write( " -2x+y=6
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Algebra.Com's Answer #14139 by Ashley1516(4)\"\" \"About 
You can put this solution on YOUR website!
OK.....To solve this problem by substitution, you first need to get either x or y by itself on one side of the equal sign. The y in eq.2(-2x+y=6) is the easiest to work with. Change the -2x to positive 2x and add to itself and 6. Like so:
\n" ); document.write( "-2x+y=6
\n" ); document.write( "+2x +2x
\n" ); document.write( "-----------
\n" ); document.write( "y=2x+6 Now you know what y is and u can substitute it into eq.1(-3x+2y=-6)! Like so:
\n" ); document.write( "-3x+2(2x+6)=-6 Now solve for x:
\n" ); document.write( "-3x+4x+12=-6
\n" ); document.write( "x+12=-6
\n" ); document.write( " -12 -12
\n" ); document.write( "----------
\n" ); document.write( "*x=-18* Now u have x!! Plug x into eq.2 to find y:
\n" ); document.write( "-2(-18)+y=6
\n" ); document.write( "36+y=6
\n" ); document.write( "-36 -36
\n" ); document.write( "---------
\n" ); document.write( "*y=-30* You now have y!!
\n" ); document.write( "YOUR ANSWER IS (x,y):
\n" ); document.write( "*-18,-30*
\n" ); document.write( "Always make sure to check your answer!
\n" ); document.write( "Just plug in your y and x into both equations:
\n" ); document.write( "-3x+2y=-6(eq.1)
\n" ); document.write( "-3(-18)+2(-30)=-6
\n" ); document.write( "54+(-60)=-6
\n" ); document.write( "-6=-6 CORRECT!
\n" ); document.write( "-2x+y=6
\n" ); document.write( "-2(-18)+(-30)=6
\n" ); document.write( "36+(-30)=6
\n" ); document.write( "6=6 CORRECT!
\n" ); document.write( "Well, I really hope this helps and you can understand it!
\n" ); document.write( "~aShLeY~
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