document.write( "Question 188548: At 12 noon, Jack leaves at 53 kph to catch Jill who had a one hour head start. If Jack was still 26 km behind @ 8 pm, how fast was Jill going? \n" ); document.write( "

Algebra.Com's Answer #141377 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"b\"$ = Jill's speed
\n" ); document.write( "For Jack:
\n" ); document.write( " $\"d%5Ba%5D+=+r%5Ba%5D%2At%5Ba%5D\"$
\n" ); document.write( "For Jill:
\n" ); document.write( " $\"d%5Bb%5D+=+r%5Bb%5D%2At%5Bb%5D\"$
\n" ); document.write( "given:
\n" ); document.write( " $\"t%5Ba%5D+=+2\"$ hr
\n" ); document.write( " $\"r%5Ba%5D+=+53\"$ km/hr
\n" ); document.write( " $\"t%5Bb%5D+=+3\"$ hr
\n" ); document.write( " $\"d%5Ba%5D+=+d%5Bb%5D+-+26\"$ km
\n" ); document.write( "----------------------
\n" ); document.write( "Rewriting equations:
\n" ); document.write( "(1) $\"d%5Bb%5D+-+26+=+53%2A2\"$
\n" ); document.write( "(1) $\"d%5Bb%5D+=+106+%2B+26\"$
\n" ); document.write( "(1) $\"d%5Bb%5D+=+132\"$
\n" ); document.write( "(2) $\"d%5Bb%5D+=+r%5Bb%5D%2A3\"$
\n" ); document.write( "(2) $\"132+=+3%2Ar%5Bb%5D\"$
\n" ); document.write( "(2) $\"r%5Bb%5D+=+132%2F3\"$
\n" ); document.write( "(2) $\"r%5Bb%5D+=+44\"$ km/hr answer \n" ); document.write( "

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