document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=188543>Question 188543</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The diagonal of a rectangle measures 15 inches and the length is 3 more than the width. Find the length and width of the rectangle.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #141373 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=141373\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We have a right triangle. The diagonal is the hypotenuse.<BR>\n" );
document.write( "Let L=w+3<BR>\n" );
document.write( "a^2+b^2=c^2<BR>\n" );
document.write( "w^2+(w+3)^2=15^2 substitute w+3 for L<BR>\n" );
document.write( "w^2+w^2+6w+9=225<BR>\n" );
document.write( "2w^2+6w-216=0<BR>\n" );
document.write( "w^2+3w-108=0 divide each side by 2.<BR>\n" );
document.write( "(w+12)(w-9)=0<BR>\n" );
document.write( "w=9\"<BR>\n" );
document.write( "L=12\"<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );